Traverse the string array in c -

Traverse the string array in c -

#include <stdio.h> int main(int argc, const char *argv[]) { const char *s[] = {"a", "b", "c", null}; const char **p = s; while (*p != null) { printf("string = %s\n", *p); (*p)++; } homecoming 0; }

i want traverse string array , print string util come null sentinal. generate terminated signal sigsegv (address boundary error)message. can tell me why?

with line :

(*p)++

you increment p[0].

i guess not want.

replace :

p++;

it should work fine ;)

c arrays string pointers