shell - How can I take a variable number of files as input for a python script? -

shell - How can I take a variable number of files as input for a python script? -

for illustration want able run hypothetical command:

$ python script.py *.txt option1 option2

and have execute on every file matches *.txt

currently have found info on operating on 1 file @ time

from sys import argv self, file, option1, option2 = argv perform_operation(file, option1, option2) #function definition

argv list. let's assume going pass filename arguments. if it's more complicated, go deets' answer.

self = sys.argv[0] arguments = sys.argv[1:]

now, arguments list of programme arguments. let's want process them 1 @ time:

for argument in arguments: work(argument)

or want pass of them function:

work(arguments)

as passing *.txt argument. shell (before programme runs) of work you.

if run, python program.py *.txt *.txt refers 3 text files, shell expand such programme see python program.py a.txt b.txt c.txt.

python shell python-2.7 command-line command-line-arguments