mysql - PHP: How to retrieve a file uploaded and saved on a web server? -

mysql - PHP: How to retrieve a file uploaded and saved on a web server? -

i uploaded file web server (i admin). based on code, location of file @ upload/. can explain can retrieve file saved on server? when run got output of

upload: fly.gif type: image/gif size: 7.6962890625 kb temp file: /tmp/phplxtnzg stored in: upload/fly.gif

i tried looking folder path couldn't find on centos machine.

thanks, linuxuser

<?php $allowedexts = array("gif", "jpeg", "jpg", "png"); $temp = explode(".", $_files["file"]["name"]); $extension = end($temp); if ((($_files["file"]["type"] == "image/gif") || ($_files["file"]["type"] == "image/jpeg") || ($_files["file"]["type"] == "image/jpg") || ($_files["file"]["type"] == "image/pjpeg") || ($_files["file"]["type"] == "image/x-png") || ($_files["file"]["type"] == "image/png")) && ($_files["file"]["size"] < 20000) && in_array($extension, $allowedexts)) { if ($_files["file"]["error"] > 0) { echo "return code: " . $_files["file"]["error"] . "<br>"; } else { echo "upload: " . $_files["file"]["name"] . "<br>"; echo "type: " . $_files["file"]["type"] . "<br>"; echo "size: " . ($_files["file"]["size"] / 1024) . " kb<br>"; echo "temp file: " . $_files["file"]["tmp_name"] . "<br>"; if (file_exists("upload/" . $_files["file"]["name"])) { echo $_files["file"]["name"] . " exists. "; } else { move_uploaded_file($_files["file"]["tmp_name"], "upload/" . $_files["file"]["name"]); echo "stored in: " . "upload/" . $_files["file"]["name"]; } } } else { echo "invalid file"; } ?>

its stored on /home/admin/web/upload/fly.gif

php mysql apache file centos6