c# - Any way to constrain a generic interface to the type that implements it? -

c# - Any way to constrain a generic interface to the type that implements it? -

public interface icloneable<t> { t clone(); } public foo: icloneable<foo> { public foo clone() { //blah } }

is there way constrain t type implements interface? (foo in case). nice enforce implementing icloneable homecoming instance of itself, , not random type fancies.

no, basically. can't generic constraints. also, can't stop them implementing interface multiple times different t (as long t satisfy where constraints, none in case).

there no where constraint allows restriction implementing type.

you kinda sorta can method parameter restriction, isn't satisfactory:

public static t superclone<t>(this t original) t : icloneable<t> {...}

c# generics interface generic-constraints