python - Is it expected behavior with os.path.join() -

python - Is it expected behavior with os.path.join() -

example1 path2 starts '/' results /dir2/dir3/ (missing path1)

path1='/volumes/disk1/' path2='/dir2/dir3/' print os.path.join(path1,path2)

example2 path2 not start '/' results proper /volumes/disk1/dir2/dir3/:

path1='/volumes/disk1/' path2='dir2/dir3/' print os.path.join(path1,path2)

question: thought purpose of os.path.join() allow avoid work of tedious work of verifying if it's mac, windows or linux file path: 1 command all. if have watch if path2 starts or not start '/' (or '\') ruins every hope had , brings ton of code... solution? don't want ugliness:

if path2 , path2.replace('\\','/')[1:] , path2.replace('\\','/').startswith('/'): path2=path2[1:]

in order work without hassle of checking separators have start without them or remove them before passing os.path.join() . in code below, show 3 ways can (live ideone example play with).

individual directories import os print os.path.join('volumes', 'disk1', 'dir2', 'dir3') split paths join path1 = '/volumes/disk1/' path2 = '/dir2/dir3/' import os # convert same above: # i.e., os.path.join('volumes', 'disk1', 'dir2', 'dir3') print os.path.join(*(path1.split(os.sep) + path2.split(os.sep))) custum bring together function

using above code, can write custom join() works either single- or multi- path strings:

def join(*paths): import os homecoming os.path.join(*[part path in paths part in path.split(os.sep)]) path1 = '/volumes/disk1/' path2 = '/dir2/dir3/' print join(path1, path2)

output:

'volumes/disk1/dir2/dir3'

python