python - How to determine file, function and line number? -
in c++, can print debug output this:
printf( "file: %s, func: %s, line: %d, log: %s\n", __file__, __function__, __line__, logmessage ); how can similar in python?
there module named inspect provides these information.
example usage:
import inspect def printframe(): callerframerecord = inspect.stack()[1] # 0 represents line # 1 represents line @ caller frame = callerframerecord[0] info = inspect.getframeinfo(frame) print info.filename # __file__ -> test.py print info.function # __function__ -> main print info.lineno # __line__ -> 13 def main(): printframe() # line main() however, please remember there easier way obtain name of executing file:
print __file__ python
No comments:
Post a Comment